Integrand size = 20, antiderivative size = 45 \[ \int \frac {(1-2 x) (2+3 x)^3}{(3+5 x)^3} \, dx=\frac {81 x}{625}-\frac {27 x^2}{125}-\frac {11}{6250 (3+5 x)^2}-\frac {97}{3125 (3+5 x)}+\frac {279 \log (3+5 x)}{3125} \]
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Time = 0.01 (sec) , antiderivative size = 45, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.050, Rules used = {78} \[ \int \frac {(1-2 x) (2+3 x)^3}{(3+5 x)^3} \, dx=-\frac {27 x^2}{125}+\frac {81 x}{625}-\frac {97}{3125 (5 x+3)}-\frac {11}{6250 (5 x+3)^2}+\frac {279 \log (5 x+3)}{3125} \]
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Rule 78
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {81}{625}-\frac {54 x}{125}+\frac {11}{625 (3+5 x)^3}+\frac {97}{625 (3+5 x)^2}+\frac {279}{625 (3+5 x)}\right ) \, dx \\ & = \frac {81 x}{625}-\frac {27 x^2}{125}-\frac {11}{6250 (3+5 x)^2}-\frac {97}{3125 (3+5 x)}+\frac {279 \log (3+5 x)}{3125} \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.07 \[ \int \frac {(1-2 x) (2+3 x)^3}{(3+5 x)^3} \, dx=\frac {9667+40520 x+40650 x^2-20250 x^3-33750 x^4+558 (3+5 x)^2 \log (-3 (3+5 x))}{6250 (3+5 x)^2} \]
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Time = 0.73 (sec) , antiderivative size = 32, normalized size of antiderivative = 0.71
method | result | size |
risch | \(-\frac {27 x^{2}}{125}+\frac {81 x}{625}+\frac {-\frac {97 x}{625}-\frac {593}{6250}}{\left (3+5 x \right )^{2}}+\frac {279 \ln \left (3+5 x \right )}{3125}\) | \(32\) |
default | \(\frac {81 x}{625}-\frac {27 x^{2}}{125}-\frac {11}{6250 \left (3+5 x \right )^{2}}-\frac {97}{3125 \left (3+5 x \right )}+\frac {279 \ln \left (3+5 x \right )}{3125}\) | \(36\) |
norman | \(\frac {\frac {2489}{1875} x +\frac {4967}{2250} x^{2}-\frac {81}{25} x^{3}-\frac {27}{5} x^{4}}{\left (3+5 x \right )^{2}}+\frac {279 \ln \left (3+5 x \right )}{3125}\) | \(37\) |
parallelrisch | \(\frac {-303750 x^{4}+125550 \ln \left (x +\frac {3}{5}\right ) x^{2}-182250 x^{3}+150660 \ln \left (x +\frac {3}{5}\right ) x +124175 x^{2}+45198 \ln \left (x +\frac {3}{5}\right )+74670 x}{56250 \left (3+5 x \right )^{2}}\) | \(51\) |
meijerg | \(\frac {4 x \left (\frac {5 x}{3}+2\right )}{27 \left (1+\frac {5 x}{3}\right )^{2}}+\frac {10 x^{2}}{27 \left (1+\frac {5 x}{3}\right )^{2}}+\frac {x \left (15 x +6\right )}{25 \left (1+\frac {5 x}{3}\right )^{2}}+\frac {279 \ln \left (1+\frac {5 x}{3}\right )}{3125}-\frac {81 x \left (\frac {100}{9} x^{2}+30 x +12\right )}{500 \left (1+\frac {5 x}{3}\right )^{2}}+\frac {81 x \left (-\frac {625}{27} x^{3}+\frac {500}{9} x^{2}+150 x +60\right )}{3125 \left (1+\frac {5 x}{3}\right )^{2}}\) | \(97\) |
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Time = 0.22 (sec) , antiderivative size = 52, normalized size of antiderivative = 1.16 \[ \int \frac {(1-2 x) (2+3 x)^3}{(3+5 x)^3} \, dx=-\frac {33750 \, x^{4} + 20250 \, x^{3} - 12150 \, x^{2} - 558 \, {\left (25 \, x^{2} + 30 \, x + 9\right )} \log \left (5 \, x + 3\right ) - 6320 \, x + 593}{6250 \, {\left (25 \, x^{2} + 30 \, x + 9\right )}} \]
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Time = 0.05 (sec) , antiderivative size = 36, normalized size of antiderivative = 0.80 \[ \int \frac {(1-2 x) (2+3 x)^3}{(3+5 x)^3} \, dx=- \frac {27 x^{2}}{125} + \frac {81 x}{625} - \frac {970 x + 593}{156250 x^{2} + 187500 x + 56250} + \frac {279 \log {\left (5 x + 3 \right )}}{3125} \]
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Time = 0.19 (sec) , antiderivative size = 36, normalized size of antiderivative = 0.80 \[ \int \frac {(1-2 x) (2+3 x)^3}{(3+5 x)^3} \, dx=-\frac {27}{125} \, x^{2} + \frac {81}{625} \, x - \frac {970 \, x + 593}{6250 \, {\left (25 \, x^{2} + 30 \, x + 9\right )}} + \frac {279}{3125} \, \log \left (5 \, x + 3\right ) \]
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Time = 0.26 (sec) , antiderivative size = 32, normalized size of antiderivative = 0.71 \[ \int \frac {(1-2 x) (2+3 x)^3}{(3+5 x)^3} \, dx=-\frac {27}{125} \, x^{2} + \frac {81}{625} \, x - \frac {970 \, x + 593}{6250 \, {\left (5 \, x + 3\right )}^{2}} + \frac {279}{3125} \, \log \left ({\left | 5 \, x + 3 \right |}\right ) \]
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Time = 0.04 (sec) , antiderivative size = 32, normalized size of antiderivative = 0.71 \[ \int \frac {(1-2 x) (2+3 x)^3}{(3+5 x)^3} \, dx=\frac {81\,x}{625}+\frac {279\,\ln \left (x+\frac {3}{5}\right )}{3125}-\frac {\frac {97\,x}{15625}+\frac {593}{156250}}{x^2+\frac {6\,x}{5}+\frac {9}{25}}-\frac {27\,x^2}{125} \]
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